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Compare a string with the string.
template< [role red error.param neither has a declname nor a 'class ' prefix in the type][role red error.param neither has a declname nor a 'class ' prefix in the type][role red error.param neither has a declname nor a 'class ' prefix in the type][role red error.param neither has a declname nor a 'class ' prefix in the type]> constexpr int compare( const T& t) const;
Let s be string_view_type(t)
and comp be traits_type::compare(data(),
s.data(), std::min(size(),
s.size()) . If comp != 0, then
the result is comp. Otherwise,
the result is 0 if size()
== s.size() , -1
if size()
< s.size() , and 1 otherwise.
Linear.
Strong guarantee.
|
Type |
Description |
|---|---|
|
|
The type of the object to convert. |
std::is_convertible<const T&, string_view>::value && !std::is_convertible<const T&, const_pointer>::value.
The result of lexicographically comparing s
and the string.
|
Name |
Description |
|---|---|
|
|
The string to compare. |